Inactive Tutor answered 03/06/23
Hi again Ju O.,
An outstanding problem. If you assume that you simply form Fe(OH)3 , you are only partly right. But more likely, you obtain a gelatinous heavy mess, which you can't filter, without a boiling digestion step first. Then you MAY obtain Fe2O3.nH2O -- in other words, hydrated ferric oxide. Which you also can't obtain a reliable value of n for, until you calcine it a bit, to drive off ALL the water.
Good luck with that.
The only other side reaction to consider is the formation of ferrites (Na(Fe(OH)4) species). But you don't have extreme enough conditions for that, I don't think. Worry about that for Al basic precipitates, though!
-- Cheers, --Mr. d.