What mass in grams of tin would be required to completely react with 1.20 L of 0.750 M HBr in the following chemical reaction? Sn(s) + 4 HBr(aq) → SnBr₄ (aq) + 2 H₂ (g)

Answer 1

1.2 L of 0.75 M HBr means 0.9 mol of HBr, namely, it needs 0/9/4=0.225 mol of Tin; The mole weight of Tin is 118.7， so the mass in grams is 118.7 x 0.225=26.7 g