What is the pH of a 8.5 × 10⁻³ M HI solution?

Answer 1

Where to start:

Identify the question: pH =?

Identify formula for pH: pH = -log[H⁺]

What's needed for this formula?: [H⁺]

Strong acids and strong bases completely dissociate, which means the concentration of a strong acid is equal to [H+].

The concentration of a strong base is equal to [OH^-]

Identify the acid: HI is one of the strong acids so the concentration of HI is equal to [H⁺]

Plug it into the formula: pH = -log(8.5 · 10^-3) = 2.07

ANSWER: 2.07

Leave a comment if you have any questions or if this was helpful :-)