Write a function get_last(nested_list) that takes in a list of lists of integers

Question

Write a function get_last(nested_list) that takes in a list of lists of integers, and returns a list containing the last integer in each inner list. If one of the inner lists is empty, then a 0 should be placed into the output list instead of the last element (since an empty list doesn't have a last element.

Examples: >>> get_last([[6, 3, 25, 4], [], [22, 16, 38]]) [4, 0, 38]

>>> get_last([[2]]) [2]

>>> get_last([[-20, 10, 2, 4, 5], [4], [8, 25, 10], []]) [5, 4, 10, 0]

Answer 1

Here's one approach using a nested helper function:

def get_last(lst):

def last_in_list(lst):

if(len(lst) > 0):

return lst[-1]

return 0

return [last_in_list(x) for x in lst]