
Jenifer B. answered 03/02/23
Passionate Science Tutor specializes in biology and beyond
- 0.584 mol C7H6O3 x 1 mol C9H8O4/1 mol C7H6O3 x 180.2 g C9H8O4/mol = 105.2 g C9H8O4 The percent yield of the reaction is calculated as follows:
- percent yield = actual yield / theoretical yield x 100%
- percent yield = 60.6 g / 105.2 g x 100% = 57.6% Therefore, the percent yield of the reaction is 57.6%.