
RIshi G. answered 03/01/23
North Carolina State University Grad For Math and Science Tutoring
pH = -log[H3O+]
1.20 = -log[H3O+]
[H3O+] = 10^(-pH)
[H3O+] = 10^(-1.20)
[H3O+] = 0.0631 M (rounded to 2 sig figs)
Suleiman N.
asked 03/01/23Convert the following pH value to concentration of H3O+: 1.20 (Keep 2 sig figs in your answer.)
I did anti log^ -1.20 and got 0.630957344 as my concentration but im not sure how to put it into the correct sigfigs.
RIshi G. answered 03/01/23
North Carolina State University Grad For Math and Science Tutoring
pH = -log[H3O+]
1.20 = -log[H3O+]
[H3O+] = 10^(-pH)
[H3O+] = 10^(-1.20)
[H3O+] = 0.0631 M (rounded to 2 sig figs)
Anthony T. answered 03/01/23
Patient Science Tutor
pH = - log [H3O1+]
[H3O1+] = 10-1.20 =0.06309... (not 0.6309...)
The question says to keep 2 sig figs in the answer, so it would be 0.063. The zero after the decimal point doesn't count as a sig fig.
Suleiman N.
Thank You!03/01/23
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Suleiman N.
wouldn't the 1 at the end make it 3 sigfigs?03/01/23