how many grams of Cl2 would be produced by 97.0 grams of PCl5?

Answer 1

The balanced chemical equation for the reaction between PCl5 and water is:

PCl5 + 4H2O → 5HCl + H3PO4

From the equation, we can see that 1 mole of PCl5 produces 5 moles of HCl.

First, we need to determine the number of moles of PCl5 in 97.0 g:

moles of PCl5 = mass / molar mass = 97.0 g / 208.24 g/mol = 0.4665 mol

Since 1 mole of PCl5 produces 5 moles of HCl, the number of moles of HCl produced is:

moles of HCl = 5 x moles of PCl5 = 5 x 0.4665 mol = 2.3325 mol

From the balanced chemical equation, we can also see that 1 mole of Cl2 is produced for every 2 moles of HCl. Therefore, the number of moles of Cl2 produced is:

moles of Cl2 = moles of HCl / 2 = 2.3325 mol / 2 = 1.16625 mol

Finally, we can calculate the mass of Cl2 produced using the molar mass of Cl2:

mass of Cl2 = moles of Cl2 x molar mass = 1.16625 mol x 70.90 g/mol = 82.6 g

Therefore, 97.0 g of PCl5 produces 82.6 g of Cl2.