What would be the percent error by going 3 drops past the equivalence point in a titration that actually requires 13.65 mL of titrant? 20 drops= approximately 1 mL.

Answer 1

First, let's determine how many mL are in 3 drops. 20 drops = 1 mL, so 3 drops is 1 mL /20 x 3 = 0.15 mL.

The percent error is given by 0.15 mL / 13.65 x 100 = 1.099%. Since 20 drops is approximately 1 mL, the answer should probably be expressed as 1%

Answer 2

Assuming that each drop is equivalent to approximately 0.05 mL (1 mL/20 drops), adding 3 drops past the equivalence point would mean adding an additional 0.15 mL (3 drops x 0.05 mL/drop).

The actual volume of titrant required is 13.65 mL, but the titration was continued beyond the equivalence point by an additional 0.15 mL. Therefore, the total volume of titrant added would be:

13.65 mL + 0.15 mL = 13.8 mL

The percent error can be calculated as:

| (13.8 mL - 13.65 mL) / 13.65 mL | x 100%

= | 0.15 mL / 13.65 mL | x 100%

= 1.1%

Therefore, going 3 drops past the equivalence point would result in a percent error of approximately 1.1%.