Math QUESTION HELP

Question

An ice freezer behind a restaurant has a freon leak, releasing 34.06 g34.06 g of C2H2F3ClC2⁢H2⁢F3Cl into the air every week. If the leak is not fixed, how many kilograms of fluorine will be released into the air over 6 months?6 months? Assume there are 4 weeks in a month.

mass of fluorine leaked over 6 months:6 months:

Answer 1

The molar mass of C2H2F3Cl can be calculated as:

2(12.01 g/mol) + 2(1.01 g/mol) + 3(19.00 g/mol) + 35.45 g/mol = 148.49 g/mol

We know that for every 1 mole of C2H2F3Cl, there are 3 moles of fluorine (F) atoms.

So, we can calculate the number of moles of C2H2F3Cl released every week as:

34.06 g / 148.49 g/mol = 0.2296 mol/week

And the number of moles of fluorine released every week as:

0.2296 mol/week x 3 mol F/mol = 0.6888 mol/week

Over 6 months, which is equivalent to 24 weeks (4 weeks/month x 6 months), the total number of moles of fluorine released would be:

0.6888 mol/week x 24 weeks = 16.53 mol

Converting moles of fluorine to grams and then to kilograms:

16.53 mol x 18.99 g/mol = 313.62 g

313.62 g = 0.31362 kg

Therefore, 0.31362 kg of fluorine will be released into the air over 6 months.