count list python

Question

Write a function named passwords(my_list), which takes a list of passwords as an argument and returns the list containing the number of digits, number of letters and number of other characters of every password in the given list. (Hint: make sure your code removes all leading and trailing blank spaces from the passwords, if any)

Examples:

passwords(['123pass', ' pass@123', '  weakpass  ']) returns [ [3,4,0] , [3,4,1] , [0,8,0] ] ->a list of lists (2D list)

Explanation: the 1st password '123pass' has 3 digits, 4 letters and 0 other characters, so the first element of the final returned list is [3,4,0]; Similarly, the 2nd password ' pass@123' has 3 digits, 4 letters and 1 other character, so the second element of the returned list is [3,4,1]; The 3rd password in the list '  weakpass  ' has 0 digits, 8 letters and 0 other characters, so the third element of the returned list is [0,8,0].

passwords([ 'p@$$wor6' , '  not()404']) returns [ [1,4,3] , [3,3,2] ]

passwords(['123456789']) returns [ [9,0,0] ]

Answer 1

While I feel like answering this question in full wouldn't be in the best spirit of learning, here's some pseudocode for a function that takes ONE password and outputs a list containing a count of the different character types in that password

def count_char_types(my_password)

remove leading and trailing blank spaces

counter for number of digits

counter for number of letters

counter for number of other chars

FOR each character in my_password

IF character is a digit

add 1 to number of digits

ELSE IF character is a letter

add 1 to number of letters

ELSE

add 1 to number of other chars

return list: number of digits, number of letters, number of other chars

If you can make this function work, you should be able to call it on each password in `my_list` that's given to the `passwords(...)` function.