
Brandon P. answered 03/02/23
MBA Grad
child-care providers that have cribs with soft bedding that can lead to suffocation, we can use the following formula:
CI = p ± zsqrt((p(1-p))/n)
where:
CI = confidence interval p = sample proportion (42/220 = 0.191) z = z-score for the desired confidence level (0.93/2 + 0.5 = 1.81) n = sample size (220)
Plugging in the values, we get:
CI = 0.191 ± 1.81sqrt((0.191(1-0.191))/220)
Solving for the upper and lower limits of the confidence interval, we get:
Lower limit = 0.105 Upper limit = 0.277
Therefore, we can be 93% confident that the true proportion of licensed child-care providers with cribs containing soft bedding that can lead to suffocation falls between 0.105 and 0.277.