Chemistry stoichiometry

Question

Fe2O3 + 2Al yields Al2O3 + 2Fe A welder has 1.873 x 10 to the second power g Fe2O3 and 94.51 g Al in his welding kit.How many grams of of aluminum oxide are produced in the reaction?

choices are 0.5867 g, 15.61 grams, or 119.6 grams. Already tried an answer, but it’s not correct.

Answer 1

Where to start:

identify what they're asking for:

how many grams of Al₂O₃ are produced?

When it asks "how much of the product (Al₂O₃) is produced" it is a limiting reactant problem

Convert each reactant to grams of Al₂O₃ to determine which makes less

1.873•10² g Fe₂O₃ x (1 mol Fe₂O₃/159.69 g Fe₂O₃) x (1 mol Al₂O₃/1 mol Fe₂O₃) x (101.96 g Al₂O₃/1 mol Al₂O₃)

= 119.59 g Al₂O₃

94.51 g Al x (1 mol Al/26.98 g Al) x (1 mol Al₂O₃/2 mol Al) x (101.96 g Al₂O₃/1 mol Al₂O₃)

= 178.58 g Al₂O₃

Since Fe₂O₃ made less, Fe₂O₃ is the limiting reactant so, the amount of Al₂O₃ produced is:

= 119.59 g Al₂O₃