(7^2 − 5) + (7^3 − 10) + (7^4 − 15) + · · · + (7^2023 − 10110)
5+10 + 15 + ... +10110 = 5(1+ 2 + ... +2022) = ...
7^2 +7^3 + ...+7^2023 = 7^2(7^0 + 7^1 + ... + 7^2021) = ...
Woojin L.
asked 02/17/23Use the formula for the sum of the first n integers and the formula
for the sum of a geometric sequence to evaluate
(7^2 − 5) + (7^3 − 10) + (7^4 − 15) + · · · + (7^2023 − 10110).
Do not compute powers of 7 for this problem. Instead, write your answer as
simply as possible without computing powers of 7. Your answer may involve 7x
for some value(s) of x.
Hint: You can rewrite this summation as a combination of two summations.
You must use the fact that for every integer n ≥ 1,
1+2+ ... n = n(n+1)/2,
and the fact that for every real number r except 1, and any integer n ≥ 0,\
n
∑ r^j = r^n+1 - 1 / r-1
.i=1
(7^2 − 5) + (7^3 − 10) + (7^4 − 15) + · · · + (7^2023 − 10110)
5+10 + 15 + ... +10110 = 5(1+ 2 + ... +2022) = ...
7^2 +7^3 + ...+7^2023 = 7^2(7^0 + 7^1 + ... + 7^2021) = ...
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