Calculate the number of atoms in a 9.16x10^3g sample of boron

Answer 1

1 Mole of Boron contains 6.023*10²³ atoms. Molar mass of Boron is 10.8 g.

10.8 g of Boron contains 6.023*10²³ atoms.

9.16*10³ g of Boron contains x atoms

x = (9.16*10³ g* 6.023*10²³ atoms)/10.8 g

= 0.848 * 10²⁶ atoms

= 8.48* 10²⁵ atoms

9.16*10³ g of Boron sample contains 8.48* 10²⁵ atoms