The proper equation comes from equating the energy gain by the water to the energy release of the hot pack.
mwcwΔT = -nΔHcryst = -(mSA/MSA)ΔHcryst
Solve for m:
mSA = mwcwΔT(MSA/(-ΔHcryst))
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Nala H.
asked 02/03/23Instant hot packs work by crystallizing sodium acetate. the molar enthalpy of crystallization of sodium acetate is -56.7 kj/mol. How many grams of sodium acetate are needed to warm 125.0ml of water from 21 degree celsius to 35.04 degree celsius.
The proper equation comes from equating the energy gain by the water to the energy release of the hot pack.
mwcwΔT = -nΔHcryst = -(mSA/MSA)ΔHcryst
Solve for m:
mSA = mwcwΔT(MSA/(-ΔHcryst))
Please consider a tutor. Take care
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