Robert P. answered 01/30/23
Recent Duke grad teaching math and physics
Ethanol Density is 0.00079kg/cm^3. cm^3/kg=1/0.000789=1267.43. (1267.43cm^3/kg)*1.35kg=1711.42cm^3=1.81 quarts
Berta W.
asked 01/30/23Explain conversions
Robert P. answered 01/30/23
Recent Duke grad teaching math and physics
Ethanol Density is 0.00079kg/cm^3. cm^3/kg=1/0.000789=1267.43. (1267.43cm^3/kg)*1.35kg=1711.42cm^3=1.81 quarts
Justin K. answered 01/30/23
Yale Graduate Specializing in Chemistry
For this question, we'll need to use the density equation: Density = mass / volume. You may have been provided with the density of ethanol in the question stem but if not, you can just look it up! The number I found online was 789 grams/liter. Since the question gives mass in kilograms, lets convert this to kilograms/liter like this: (789g/L) * (1kg/1000g) = .789kg/L.
So, now we can set our density (.789kg/L) equal to the given mass (1.35kg) divided by volume (what we're looking for!).
.789 = 1.35kg / xL
Solving for x, we find that x = 1.71 L.
But we want to know the volume in quarts, right? So we're not quite done! Now we just have to convert Liters to quarts! 1 Liter is equal to 1.057 quarts so we can multiply our answer by this number to get our final answer.
1.71 L * 1.057 = 1.81 quarts
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