Hi Nathan W.!
This is a rather straightforward application of stoichiometry. We simply convert our mass of nitric acid into moles, so we can use the stoichiometric ratios provided in the balanced equation to our advantage:
(135.8g HNO3)(1 mol HNO3/63g HNO3)(2 mol H2O/6 mol HNO3)
mass = 0.7g H2O
Hope this helps!
Cheers