loops arrays interation

Question

Where is Waldo (again)

1. With the following multi-dimensional array

const whereIsWaldo = [["Picard", "Riker"], "Data",["Beverly", "Guinan", "Q", "Geordi"],["Deanna", ["Worf", "Wesley"]]];

1. Remove Data (hint look at the slice/splice method(s))
2. Change "Q" to "No One"
3. Access and console.log "Wesley"

Answer 1

# Note: No const in Python

whereIsWaldo = [["Picard", "Riker"], "Data",["Beverly", "Guinan", "Q", "Geordi"],["Deanna", ["Worf", "Wesley"]]];

def slice_demo():

modified = [whereIsWaldo[0]] # eliminate 'Data' == copy all elements except 'Data'

modified.extend(whereIsWaldo[2:])

modified[1] = [el.replace('Q', 'No One') for el in modified[1]] # change 'Q' to 'No One'

wesleys = [x for x in modified[2][1] if x == 'Wesley'] # make a list of all the Wesleys (just one)

wesley = wesleys[0] # grab the one and only Wesley

print(f'wesley is: {wesley}') # and log it to the console

def main():

slice_demo()

if __name__ == '__main__':

main()

#============================================

# OUTPUT

#

# wesley is: Wesley

#============================================