
Stanton D. answered 12/31/22
Tutor to Pique Your Sciences Interest
What specifically is your question? The provided information is data; the necessary transformations include:
1) calculate the mass of CuSO4 (anhydrous) product
2) calculate the moles of CuSO4 (anhydrous) that this represents (use formula weight CuSO4)
3) calculate mass lost = water mass lost
4) convert water mass lost into moles water lost (use molecular mass H2O)
5) Divide (4) by (2), and express in integer ratio.
(H) I and II require a little thought. Assume conversion to (1/2) hydrate (i.e. CuSO4.(0.5)H2O), and work through the calculations based on that **using the correct ratio you just obtained in (5)** ; for II, assume conversion of 0.1 proportion of the CuSO4 to CuO and work through the calculations similarly. The answers will show you what happens to the mass lost. However, for case I, note that you will arrive experimentally at a hydration number less than the correct formula value, whereas, for the case II, you will arrive at a hydration value greater than that for the correct formula.
Now for the fun part of any experiment, which is figuring out IN ADVANCE what you might do to recover from such errors! (Bt the way, this is valuable strategy for succeeding in the world, in general!)
For case I, if you did not get an integer value for hydration number, what might you do to see if you could get closer to the correct value? And for case II, what could you do (in terms of recovering CuO, and quantitating it!), to eventually provide a path to the correct value?
You might think that these are purely hypothetical problems, and so they might be, for CuSO4.xH2O; however, there are experimental situations in which arriving exactly to a desired endpoint is difficult or impossible, and you MUST go beyond, and then compensate, for example by back-titration. Or, use some other means of observing. Case in point: determining the melting point of certain organic materials, which are starting to decompose already at their melting point! Indeed, the antiviral drug ribavirin is such: at the melting point, as it starts melting, bubbles are trapped in the viscous melt, which make easy observation of the exact melting range impossible by eye. So instead, an instrumental device (differential scanning calorimeter) may be used, which detects the heat absorption associated with the melt process, and then mathematically transforms the data back into a temperature range, using previously measured rates of temperature lag from the sample to the detector thermocouple. In this way, the melting range may be rapidly scanned (minimizing decomposition of the substance), and a precise range obtained.