
Wail S. answered 12/12/22
Experienced tutor in physics, chemistry, and biochemistry
Hi Leah,
To describe radioactive decay, we can use the concept of natural decay from mathematics. The derivation comes from Calculus, so I will skip that unless you would like me to show you (let me know)
The equation is:
N = N0 e-kt
where N is the amount of material at any point in time, N0 is the starting amount of the material (at t=0), e is Euler's number, k is the decay constant (specific to the material of interest), and t is time
You are given that the half-life is 12.5 years, this means that if we start with X amount of material and wait 12.5 years, we will only have (1/2)X material left.
Let's model this half-life using our equation above:
N = N0 e-kt
N/N0 = e-k(12.5 years) = 1/2
note: N/N0 = 1/2 because this is what half-life means: the final N is half of N0, so dividing them gives 1/2
So this becomes
1/2 = e-k(12.5 years)
We can solve this for k by taking the natural logarithm of both sides, this gives:
ln(1/2) = ln (e-k(12.5 years) )
ln(1/2) = -k(12.5 years)
k = - ln(1/2) / 12.5 years = 0.055 1/years (1/years is the unit for this decay constant)
We just derived our decay constant for this material, so now our decay equation can be written:
N = N0 e-0.055t
To solve our problem, we plug in 8.00 grams for N0, and 50.0 years for t in the above equation and solve for N as our answer