one mole of sodium bicarbonate(NaHCO3)reacting with one mole of hydrochloric acid(HCl)to produce one mole of carbonic acid (H2CO3),and one mole of sodium chloride(NaCl).

Question

Using this chemical stoichiometry, determine the number of moles of carbonic acid that can be produced from 5 mol NaHCO3 and 7 mol HCl. And excess reactant in moles

Answer 1

NaHCO3+HCl. --> NaCl+H2CO3

the stoichiometry is 1,1,1,1 respectively for each compound from left to right.

moles of NaHCO3/1 =5 < moles of HCl/1=7

so HCl is excess reactant

moles of H2CO3=moles of NaHCO3=5 mol