How many grams of hydrochloric acid are required to react completely with 61.8 grams of calcium hydroxide HCl + Ca(OH)2 → CaCl2 + H2O

Question

How many grams of hydrochloric acid are required to react completely with 61.8 grams of calcium hydroxide according to the following unbalanced chemical equation?

HCl + Ca(OH)₂ → CaCl₂ + H₂O

Answer 1

I hope this helps!

Step 1. Balance the Equation:

2HCl + Ca(OH)₂ → CaCl₂ + 2H2O

Step 2. Determine the moles of reactant using the molar mass of calcium hydroxide.

(61.8 g Ca(OH)₂) / (74.09 g/mol) = 0.83 mol Ca(OH)₂

Step 3. Use the mole ratio from step 2 to find moles of HCl.

0.83 mol Ca(OH)₂ x 2 mol HCl / 1 mol Ca(OH)₂ = 1.66 mol HCl

Step 4. Use the molar mass of HCl (step 3) to find the grams of HCl needed.

1.668 mol HCl x 36.458 g/mol = ______ g HCl