N2 + H2 → NH3 If an excess of nitrogen is reacted with 3.41 g of hydrogen gas, how many grams of ammonia can be produced?

Question

Ammonia is synthesized from hydrogen gas and nitrogen gas according to the following unbalanced equation:

N₂  + H₂  →  NH₃  

If an excess of nitrogen is reacted with 3.41 g of hydrogen gas, how many grams of ammonia can be produced?

Answer 1

Given: 3.41 g of hydrogen gas

Balanced Equations

N₂  + 3H₂  →  2NH₃   

Molar Mass of each

N₂ = 28.02 g/mol

H₂ = 2.016 g/mol

NH₃ = 17.031 g/mol

Since we have excess nitrogen molecule, hydrogen molecule is the limiting factor in this reaction.

From balanced equations we know that 3 moles of hydrogen molecules produce 2 moles of ammonia.

So, from reactions above we use 3moles X 2.016 g/mol = 6.048g Hydrogen gas to produce 2mol X 17.031g/mol = 34.062g ammonia.

If we have 3.41 g of hydrogen gas, we can calculate by Criss crossing from above relationships.

6.048g = 34.062g

3.41g =?

(3.41g X 34.062g)/6.048g =?

we can get 19.104g of ammonia