2KClO3⟶2KCl+3O2 If this reaction produced 27.3 g KCl, how many grams of O2 were produced?

Answer 1

Conceptual Plan: g KCl ==> moles of KCl ==> moles of O₂ ==> g of O₂

27.3 g KCl x 1 mole KCl / 74.55 g KCl x 3 moles O₂ / 2 moles KCl x 32 g O₂ / 1mole O₂ = 17.6 g O₂.