If a tree dies and the trunk remains undisturbed for 1.270 × 10⁴ years, what percentage of the original ¹⁴C is still present? (The half-life of ¹⁴C is 5730 years.)

Question

If a tree dies and the trunk remains undisturbed for 1.270 × 10⁴ years, what percentage of the original ¹⁴C is still present? (The half-life of ¹⁴C is 5730 years.)

Answer 1

N/N₀ = 2^(-t/t_1/2) or (1/2)^(t/t_1/2)

N/N₀ in % = 100(2^(-1.27 x 10⁴/5730) = 21.52%

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