i am going to solve a problem which is my college assignment??????

1. The parabola opens downward. (a<0)

2. The vertex is at point (0, 12)

3. The max. value in this function is {12}.

4. The axis of symmetry is y-axis.

5. What is the x- and y-intercepts?

- for the x-intercept, we take the equation y = 12 - x^{2} and set y to zero and solve for x.

12 - x^{2} = 0 ---> x^{2} = 12 ---> x = ±√12 the graph crosses the x-axis at - √12 and +√12.

- for the y-intercept, likewise, set the x at zero and solve for y. This gives us 12.