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I need help with this equation

Given the equation -5 (x - 2)' -1= ,
a. Identify the vertex.
b. Identify the axis of the symmetry.
c. Identify the direction of the graph (whether it opens up or down).

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The equation that is given is the equation o0f a straight line. Please make this clear.
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1 Answer

I assume the equation is -5(x-2)2 - 1 = y
 
Let's add one to both sides:
 
-5(x-2)2 = y + 1
 
This is the equation of a parabola in "vertex" form:
 
a(x-h)2 = (y-k)
 
a)  The Vertex is located at the point (h,k)
 
b)  The line of symmetry is y = h
 
c)  The parabola opens upward if a>0, down if a<0