I need help with this equation

Question

Given the equation -5 (x - 2)' -1= ,
a. Identify the vertex.
b. Identify the axis of the symmetry.
c. Identify the direction of the graph (whether it opens up or down).

Answer 1

I assume the equation is -5(x-2)² - 1 = y

 

Let's add one to both sides:

 

-5(x-2)² = y + 1

 

This is the equation of a parabola in "vertex" form:

 

a(x-h)² = (y-k)

 

a)  The Vertex is located at the point (h,k)

 

b)  The line of symmetry is y = h

 

c)  The parabola opens upward if a>0, down if a<0