Q = mcΔT = (18.3 g)(.449 J/g-°C)(356.6 -23.8 °C)
McKenna C.
asked 12/04/22I need answer to study for chem finals
How much heat must be applied to a 18.3-g sample of iron (SH = 0.449 J/(g · °C)) in order to raise its temperature from 23.8°C to 356.6°C?
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