Ed D. answered • 01/15/23
PhD in chemsitry with a strong background in analytical chemistry
We can first calculate the number of moles of HCl at the given concentration and volume as follows:
moles HCl = 0.03M x 0.075 L = 0.00225 moles HCl
Therefore, since HCl is a strong acid, an equal number of -OH ions (strong base) is required to neutralize this acid.
However, since Ca(OH)2 dissociates into 2 -OH ions, half the number of Ca(OH)2 moles is required to neutralize the acid. Thus we simply divide the number by 2 to calculate the moles needed to neutralize the acid:
0.00225/2 = 0.001125 moles Ca(OH)2 required
Finally, now that we have the number of moles of Ca(OH)2 and concentration of the Ca(OH)2 solution that was given to us, we can calculate the volume of the Ca(OH)2 solution required for neutralization:
volume = moles Ca(OH)2/concentration of Ca(OH)2 solution = 0.001125/0.02 = 0.05625 L = 56.25 mL
