By how much would the machinist have to lower the temperature (in °C) of the rod to make it fit the hole?

Question

A machinist wishes to insert an iron rod with a diameter of 4 mm into a hole with a diameter of 3.994 mm. By how much would the machinist have to lower the temperature (in °C) of the rod to make it fit the hole?

Answer 1

Use coefficient of linear expansion = 11E-6 ... ΔD=11E-6ΔT where D= Diameter and T= Temperature. Thus ΔT=-.006/11E-6=-550 C