Density of a rectangular block and it's maximum possible error

Question

The dimensions of a rectangular glass block are length L=46.23±0.01cm, breath w=3.14±0.02cm and the thickness t=2.015±0.005.

If the mass of the block is 40.200±0.006g calculate the density and it's maximum possible error

Answer 1

Volume _max=(40.24)*(3.16)*(2.02)=256.86cc. Volume _min=(46.22)*(3.12)*(2.01)=289.85cc. Mass _max = 40.206 gm and Mass _min=40.01. Density _max = 40.206/289.85 = .1388 gm/cc and density _min = 40.01/286.86=.1395 gm/cc thus the density is .1392 ± .00035 gm/cc