Step 1: How many moles of NaOH are present in 27.5 mL of 0.180 M NaOH? moles of NaOH:

Answer 1

Concentration in molarity = moles of solute dissolved/ volume of the solution in liters

M = mol / V ……..(1)

equation (1) can be manipulated to calculate the number of moles.

mol = M * V. ……..(2)

in this problem: M = 0.180 M, V = 27.5 mL ( volume has to be in liters, you need to convert the volume in mL to L)

1 mL = 0.001 L

so, 27.5 mL = 27.5 mL x 0.001L / 1 mL. = 0.0275 L

substitute the number of moles and volume in L in equation (2)

moles of NaCl = 0.180 M. x 0.0275 L = 0.00495 mole.