Danyal A. answered • 6d
Middle & Early High School Tutor: I make Math and Chemistry fun!
First of all, we will need the balanced chemical reaction for Cobalt Nitrate and Sodium Phosphate (Sodium Phosphate is Na₃PO₄ btw). I copied this from ChatGPT just to save some time (but I encourage you to practice balancing the chemical equation if that's what you're going for):
3Co(NO₃)₂+2Na₃PO₄→CO₃(PO₄)₂+6NaNO₃
Based on this reaction:
3 mol of Co(NO₃)₂ reacts with 2 mol of Na₃PO₄ to give us -----> 1 mol of CO₃(PO₄)₂ and 6 mol of NaNO₃
Based on the information provided in the question, I would have to assume that both compounds have a volume of 1 mL (since no total volume information was provided). So we can certainly solve this question based on this assumption.
This means that the total mass of both reactants is:
Cobalt Nitrate - Co(NO₃)₂ : 0.0183g
Sodium Phosphate - Na₃PO₄ : 0.0156g
Next, we need to calculate the total moles available to us (since chemical reactions work on moles not mass). For that we need the molar mass of the reactants (again I copied them from ChatGPT, but feel free to calculate them for practice):
Co(NO₃)₂ molar mass = 182.94 g/mol ≈ 183 g/mol
Na₃PO₄ molar mass = 163.94 g/mol ≈ 164 g/mol
Co(NO₃)₂ moles = 0.0183 / 183 = 0.0001 mol
Na₃PO₄ moles = 0.0156 / 164 = 0.0000951 mol
Since the reactants react in a 3:2 ratio, Co(NO₃)₂ is the limiting reactant as all of it will be used up first. All of the available Co(NO₃)₂ will react with 0.0001 * (2/3) = 0.0000667 mol Na₃PO₄
ANSWER:
0.0001 mol of Co(NO₃)₂ reacts with 0.000067 mol of Na₃PO₄ in a 3:2 ratio to create:
Cobalt phosphate, Co₃(PO₄)₂
3 Co(NO₃)₂ → 1 Co₃(PO₄)₂
0.0001 * 1/3 = 0.0000333 mol
Sodium nitrate, NaNO₃
3 Co(NO₃)₂ → 6 NaNO₃, which is 1 → 2
0.0001 * 2 = 0.0002 mol
(REMEMBER: Product ratios are determined in relation to the limiting reactant, in this case Co(NO₃)₂)
:)
