Isayah C. answered 11/06/22
College Undergraduate Tutor for Students K-12
Hello Simrat,
To solve this problem you would first need to convert the molarity of the HCl to moles by multiplying the molarity by the volume in liters. Then you would use the reaction given to find that 1 mol HCl is equivalent to 1 mol NaHCO3. Finally, you would use the periodic table to find the grams per mol ratio of NaHCO3. So the dimensional analysis would look something like this:
(.022 mol HCl / 1 L) x (.250 L) x (1 mol NaCO3 / 1 mol HCl) x (84.01 grams NaCO3 / 1 mol NaCO3)
This would equal .462055, which approximates to .46 grams NaCO3 after rounding to significant figures.