Determine the rise, run, and slope of the line formed by these points.

Question

Consider the reaction data.

A--->product 

T(K) k(s^-1)

325 0.373

875 0.875

What two points should be plotted to graphically determine the activation energy of this reaction? To avoid rounding errors, use at least three significant figures in all values.

x1= y1=

x2= y2=

Determine the rise, run, and slope of the line formed by these points.

rise= run=

slope=

What is the activation energy of this reaction?

Ea=

Answer 1

In this case, temp is (x), while equilibrium constant k is (y)

a. rise: y₂ - y₁ = k₂ - k₁ = 0.875 - 0.372 = 0.503

b. run: x₂ - x₁ = T₂ - T₁ = 875 - 325 = 550.000 k

c. y₂ - y₁/ x₂ - x₁ = 0.000915 == 0.001

d. ln(k₁/k₂) = (Ea/R)((1/T₂) - (1/T₁))

Ea = ((RT₁T₂)/(T₁ - T₂))ln(k₁/k₂)

R = 8.314 J/Kmol

Ea = ((8.314 x 875 x 325)/(875 - 325))ln(0.372/0.875))

Ea = -3676.820 J