Help me please!

Question

Sodium chlorate decomposes into sodium chloride and oxygen gas as seen in the equation below.

 

­­2NaClO3­ --> 2NaCl +3O2

 

How many grams of NaClO3­ were needed to produce 6 grams of O2? Round your answer to the nearest whole number.

Round your answer to the whole number. If your answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element	Molar Mass
Sodium	23
Chlorine	35.5
Copper	63.5
Oxygen	16

Answer 1

First, find how many moles of O2 will be produced:

(6 g) / (32 g/mol) = 3/16 moles

Every 3 moles of O2 produced requires 2 moles of NaClO3 (based on the balanced equation). So you can calculate the moles of NaClO3 required to produce 3/16 moles of O2:

3/16 moles of O2 x (2 moles of NaClO3 / 3 moles of O2) = 1/8 moles of NaClO3

Lastly convert the moles of NaClO3 required to grams:

1/8 moles x (23 + 35.5 + 48 g/mol) = grams of NaClO3