For a particular gaseous reaction, ΔH° = 32.0 kJ/mol and ΔS° = 98.0 J/K*mol. Assume that ΔH and ΔS do not vary with temperature.

Question

a. What is the maximum work that can be done by this reaction at 298.15 K?

b. What is the equilibrium constant K_p for this reaction at 350.0 K?

Answer 1

1) W = ΔG⁰ = ΔH⁰ - TΔS⁰ where T is in Kelvin and H must be in Joules

2) K = e^(-ΔG⁰/RT) G in J/mol K, R = 8.314 J/mole K and T in Kelvin.