Nicolo B. answered 10/25/22
Experienced Tutor specializing in Pre-Medical Courses
Equations:
pH = -log [H]
[H] = 10^ -pH
pOH = -log [OH]
[OH] = 10^ -pOH
pH + pOH = 14
Converting pH to pOH
9.77 + pOH = 14
pOH = 14 - 9.77 = 4.23
Converting pOH to [OH]
pOH = -log [OH]
4.23 = -log [OH]
10^ -pOH = [OH]
[OH] = 10^ -4.23 = 5.89*10^5 M