Chemistry- volume of carbon dioxide (in L)

Question

What volume of carbon dioxide (in L) will 2.00 g of antacid made of calcium carbonate produce at 37.0 °C and 1.00 atm in the stomach according to the following reaction?

CaCO₃ (s) + 2 HCl (aq) → CaCl₂ (aq) + H₂O (l) + CO₂ (g)

Answer 1

The first step is stoichiometry to find the number of mol of CO₂ produced in the reaction.

The molar mass of CaCO3 is 100.09 g/mol

2.00g CaCO₃ × (1 mol CaCO₃/100.09 g CaCO₃) × (1 mol CO₂/1 mol CaCO₃) = 0.019982 mol CO₂

The second step is to use this number of mol as n in the ideal gas equation PV = nRT

P = 1 atm (given in the question)

R = 0.082056 L•atm/mol•K (ideal gas constant)

T = 310 K (37°C)

(1atm)V = (0.019982 mol)(0.082056 L•atm/mol•K)(310 K)

V = 0.508 L to three significant figures.