How many milliliters?

Question

How many milliliters of 0.20 M HCl is required to neutralize 90.0 mL of 0.80 M NaOH?

Answer 1

Start with the chemical reaction equation:

HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O

Notice that it takes 1 mole of HCl to react with 1 mole of NaOH.

Starting with 90.0 ml (0.090 L) of 0.80M (i.e., 0.80 moles/L) NaOH, we can calculate the equivalent number of moles:

(0.090 L)(0.80 moles/L) = 0.072 moles of NaOH. So we need 0.072 moles of HCl. Given that we have 0.20M (i.e., 0.20 moles/L) we can calculate the volume of HCl required:

(0.072 moles)/(0.20 moles/L) = 0.36 L

Since we are asked for the volume in mL, multiply by 1000 to get 360 mL of 0.20M HCl