Question below..

Question

The unbalanced equation for the reaction between propane (C₃H₈) and oxygen gas is shown below.

Balance the equation (enter the smallest integer possible in each box, including the integer "1" when needed) and determine the amount of O₂ consumed and the amounts of CO₂ and H₂O produced when 0.935 mol of C₃H₈ reacts.

1. _C₃H₈ (g) + _O₂ (g) _CO₂ (g) + _H₂O (g)
2. 
   
3. _____ mol O₂ consumed
4. _____ mol CO₂ produced
5. _____ mol H₂O produced

Answer 1

 _C₃H₈ (g) + _5O₂ (g)→ _3CO₂ (g) + 4_H₂O (g)

Balance carbon - add 3 in front of CO₂

Balance hydrogen - add 4 in front of H₂O

Balance oxygen - add 5 in front of O₂

0.935 mol of C₃H₈ x (5 mol O₂/1 mol C₃H₈) = 4.68 mol O₂ is consumed

0.935 mol of C₃H₈ x (3 mol CO₂/1 mol C₃H₈) = 2.81 mol CO₂ is produced

0.935 mol of C₃H₈ x (4 mol H₂O/1 mol C₃H₈) = 3.74 mol H₂O is produced