Calculate the number of hydrogen atoms in a 120.0g sample of camphor

Answer 1

Camphor: C₁₀H₁₆O.

Molar Mass of Camphor = 10*MM(C) + 16*MM(H) + MM(O)

MM_C10H16O = 10(12.01 g/mol)+16(1.008 g/mol) + (16 g/mol)

MM_C10H16O = 152.228 g/mol

In a sample of 120.0 g of Camphor, we can find its moles using simple stoichiometry:

120g Camphor: C₁₀H₁₆O.

Molar Mass of Camphor = 10*MM(C) + 16*MM(H) + MM(O)

MM_C10H16O = 10(12.01 g/mol)+16(1.008 g/mol) + (16 g/mol)

MM_C10H16O = 152.228 g/mol

In a sample of 120.0 g of Camphor, we can find its moles using simple stoichiometry:

120.0 g _C10H16O / 152.228g _C10H16O / mol

= 0.7883 mol _C10H16O

The number of molecules of C₁₀H₁₆O in this sample of moles is:

0.7883 mol * N_A

= 0.7883 mol * 6.022 * 10²³ molecules/mol

= 4.747 * 10²³ molecules of C₁₀H₁₆O, but there are 16 Hydrogen atoms per molecule, so:

4.747 * 10²³ molecules of C₁₀H₁₆O * 16 H atoms / molecule

= 7.595*10²⁴ atoms of Hydrogen

I hope this helps! :)