The gas in a 275.0 mL piston experiences a change in pressure from 1.00 atm to 3.10 atm. What is the new volume (in mL) assuming the moles of gas and temperature are held constant?

Answer 1

P1V1 = P2V2

1 atm (275 mL) = 3.10 atm V2

V2 = 275 mL divided by 3.10

V2 = 88.71 mL

Check

1(275) = 3.1 (88.71) = 275