what is the answer?

Question

The specific heat of a certain type of metal is 0.128 J/(g⋅∘C). What is the final temperature if 305 J of heat is added to 46.0 g of this metal, initially at 20.0 ∘C?



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Answer 1

Use the equation:

Where Q is the heat put into the metal, m is the mass of the metal, C_p is the specific heat of the metal, T_f is the final temperature of the metal and T_i is the initial temperature of the metal.

Q = 305 J

m = 46 g

C_p = 0.128 J/(g°C)

T_i = 20.0 °C

So, plugging these values into the equation:

305 = (46)(0.128)(T_f - 20.0)

305/(46•0.128) = T_f - 20.0

51.8 = T_f - 20.0

T_f = 51.8 + 20.0 = 71.8 °C