
Nurit H. answered 10/06/22
MD student with 8+ years tutoring experience
ΔG=ΔG0+ RTlnQ
ΔG=-17.09E3J/mol +(8.3145J/molK)(298)ln(1/.04x.001)
ΔG=-4.28E5 kJ/mol
Kar B.
asked 10/05/22Consider the reaction: ICl(g) + Cl₂(g) → ICl₃(s). The ∆G° of the reaction is -17.09 kJ/mol. Calculate the ∆G, in kJ/mol, for the reaction at 298 K if the partial pressure of ICl(g) is 0.0400 atm and the partial pressure of Cl₂(g) is 0.00100 atm.
Nurit H. answered 10/06/22
MD student with 8+ years tutoring experience
ΔG=ΔG0+ RTlnQ
ΔG=-17.09E3J/mol +(8.3145J/molK)(298)ln(1/.04x.001)
ΔG=-4.28E5 kJ/mol
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