Chemistry PLS HELP

Question

Calculate [H3O+] for a 1.50×10−2 M KOH solution.

Answer 1

KOH is a strong base. So it will ionize completely.

KOH  K⁺ + OH^-

So, [KOH] = [OH^-] = 1.50 x 10^-2 M

[H₃O⁺] = K_w/[OH^-] = 10^-14/(1.50 x 10^-2)

[H₃O⁺] = 6.66 10^-13 M