is this answer is correct

Question

one test tube contains some acid and another test tube contains an equal quantity of water. to prepare a solution, 20 gram of the acid is poured into the second test tube. then two third of the so formed solution is poured from the second tube into the first. if the fluid in first test tube is four times that in the second, what quantity of water was taken initially

 

acid =x, water=x

4[1/3(x+20)]=x+2/3(x+20)

Answer 1

At the beginning

 

acid = x

water = x

 

First move:

acid = x- 20

water = x + 2

 

Second move:

acid = (x - 20) + 2/3(x + 2)

water = 1/3(x + 2)

 

End statement

acid = 4 water

(x - 20) + 2/3(x + 2) = 4(1/3)(x + 2)