Change in oxidation

Question

3HNO2 + ClO3-3NO3- + Cl-+ 3H+

In the above redox reaction, use oxidation numbers to identify the element oxidized, the element reduced, the oxidizing agent and the reducing agent.

1. 
   

name of the element oxidized:			name of the element reduced:
formula of the oxidizing agent:		formula of the reducing agent:

Answer 1

NO₂^- ⇒ NO₃^- ox.

ClO₃^- ⇒ Cl^- red.

From the original meaning of the words adding 0 is oxidation and losing O is reduction.

Using Ox. Numbers and the Rules:

NO₂^- O reacted is -2 (unless a peroxide or OF₂). The sum of the oxidation states of the elements is equal to the overall charge: O_N + 2(-2) = -1 O_N = +3

NO₃^- (same logic) O_N = + 5 (N in nitrate is more oxidized than in nitrite)

Cl^- Monatomic ions have the overall charge divided by the number of atoms. Here O_Cl = -1

ClO₃^- (same logic as NO₃^-) O_Cl=+5 so Cl got reduced going from chlorate to chloride.

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