Probability and statistics

Question

Diane is putting 12 colored light bulbs into a string of lights. There are 3 vellow light bulbs, 6 blue light bulbs, and 3 orange light bulbs. How many distinct orders of light bulbs are there if two light bulbs of the same color are considered identical (not distinct)?

Answer 1

Answer:

12 bulbs, as such, can be put in a string in 12! ways.

But there are no distinctions between 3 yellow light bulbs, 6 blue light bulbs, and 3 orange light bulbs.

Hence, Ans: 12! / (3! * 6! * 3!) = 18480 distinct orders.