The rate constant at 669 K is 9.15 x 10^-4s^-1. The rate constant will be 0.00501s^-1 at ________K.

Question

The activation energy for the gas phase isomerization of methyl cis-cinnamate is 174 kJ.

cis-C₆H₅CH = CHCOOCH₃ --> trans-C₆H₅CH = CHCOOCH₃

The rate constant at 669 K is 9.15 x 10^-4s^-1. The rate constant will be 0.00501s^-1 at ________K.

Answer 1

k= Ae^-EA/RT

Let k_i = k at T_i By taking the ratio of the k's...

k₂/k₁ = exp(-(E_A/R)(1/T₂ - 1/T₁)) We now can solve for 1/T₂ by rearranging algebraically:

-(R/E_A)ln(k₂/k₁) + 1/T₁ = 1/T₂

You can substitute into the formula. Make sure E_A is 174000 J/mole, R is 8.314 J/mole-K, and T is in Kelvin.

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